\[
f(x)=\left\{\begin{array}{ll}
x^{2} & x \leq-2 \\
2 x & -2< x< 2 \\
0 & x \geqslant 2
\end{array}\right.
\]
find $f(0)$

Answer

Expert–verified

Hide Steps

Answer

Final Answer: $f(0) = \boxed{0}$

Steps

Step 1 ：Since 0 is greater than -2 and less than 2, it falls under the second condition. Therefore, we need to apply the function $2x$ to 0.

Step 2 ：Substitute $x = 0$ into the function $2x$.

Step 3 ：Calculate the value of the function, which is $2 * 0 = 0$.

Step 4 ：Final Answer: $f(0) = \boxed{0}$