f(x)=frac{250}{1+7 e^{-3 x}}. Find the carrying capacity.

Question

Accepted Answer

Step:1 ：The carrying capacity of a function is the maximum output value of the function. In this case, the function is a logistic growth function, which has the form (f(x) = frac{C}{1 + Ae^{-Bx}}), where (C) is the carrying capacity.Step:2 ：Therefore, the carrying capacity of this function is 250.Step:3 ：Final Answer: The carrying capacity is (boxed{250}).

Answer

Step: 1 ：The carrying capacity of a function is the maximum output value of the function. In this case, the function is a logistic growth function, which has the form (f(x) = frac{C}{1 + Ae^{-Bx}}), where (C) is the carrying capacity.Step: 2 ：Therefore, the carrying capacity of this function is 250.Step: 3 ：Final Answer: The carrying capacity is (boxed{250}).

$f(x)=\frac{250}{1+7 e^{-3 x}}$. Find the carrying capacity.

Answer

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