A car accelerates from rest up to a velocity of $12.5 \mathrm{~m} / \mathrm{s}$. If this process took 4.20 seconds, determine the acceleration of the car.
1 point
$1.73 \mathrm{~m} / \mathrm{s}^{\wedge} 2$
$2.98 \mathrm{~m} / \mathrm{s}^{\wedge} 2$
$3.40 \mathrm{~m} / \mathrm{s}^{\wedge} 2$
$4.87 \mathrm{~m} / \mathrm{s}^{\wedge} 2$
None of the Above

Step 1 ：The acceleration of an object can be calculated using the formula: \(a = \frac{{v_f - v_i}}{{t}}\) where \(a\) is the acceleration, \(v_f\) is the final velocity, \(v_i\) is the initial velocity, and \(t\) is the time.

Step 2 ：In this case, the car starts from rest, so \(v_i = 0\). The final velocity \(v_f\) is 12.5 m/s and the time \(t\) is 4.20 seconds.

Step 3 ：We can substitute these values into the formula to find the acceleration: \(v_f = 12.5\), \(v_i = 0\), \(t = 4.2\).

Step 4 ：Calculating the above values, we get \(a = 2.9761904761904763\).

Step 5 ：The acceleration of the car is approximately 2.98 m/s². This value is very close to the second option, so it seems that the correct answer is 2.98 m/s².

Step 6 ：Final Answer: The acceleration of the car is approximately \(\boxed{2.98 \, \mathrm{m/s}^2}\).