Find the average value of the function $g(t)=e^{t}$ over the interval $[0,5]$.
Round your answer to one decimal place.

Step 1 ：Find the average value of the function \(g(t) = e^t\) over the interval \([0, 5]\).

Step 2 ：Use the formula for the average value of a function: \(\text{average} = \frac{1}{b-a} \int_{a}^{b} f(x) dx\)

Step 3 ：Substitute the function and interval: \(\text{average} = \frac{1}{5-0} \int_{0}^{5} e^t dt\)

Step 4 ：Calculate the integral: \(\int_{0}^{5} e^t dt = e^5 - e^0\)

Step 5 ：Substitute the integral result into the average formula: \(\text{average} = \frac{1}{5}(e^5 - e^0)\)

Step 6 ：Calculate the average value: \(\text{average} = 29.482631820515333\)

Step 7 ：Round the average value to one decimal place: \(\boxed{29.5}\)