Problem

(a) What is the derivative of $\sin t$ ?
\[
\frac{d}{d t} \sin t=
\]
(b) The velocity of a particle at time $t$ is $v(t)=\cos t$. Use the Fundamental Theorem of Calculus to find the displacement of the particle between $t=0$ and $t=\frac{15 \pi}{2}$.
\[
\int_{0}^{\frac{15 \pi}{2}} \cos t d t=
\]

Answer

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Answer

\(\boxed{-1}\)

Steps

Step 1 :\(\frac{d}{d t} \sin t = \cos t\)

Step 2 :\(\int_{0}^{\frac{15 \pi}{2}} \cos t d t = \sin t \Big|_{0}^{\frac{15 \pi}{2}}\)

Step 3 :\(= \sin\left(\frac{15 \pi}{2}\right) - \sin(0)\)

Step 4 :\(= -1 - 0\)

Step 5 :\(\boxed{-1}\)

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