a) f(x)=x^{2}-2 x-3

Question

a) f(x)=x^{2}-2 x-3

Accepted Answer

Step:1 ：Given the quadratic equation: (f(x) = x^2 - 2x - 3)Step:2 ：Use the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a})Step:3 ：Substitute the coefficients: a = 1, b = -2, c = -3Step:4 ：Calculate the discriminant: (b^2 - 4ac = 16)Step:5 ：Find the roots: (x = frac{-(-2) pm sqrt{16}}{2(1)})Step:6 ：(x = frac{2 pm 4}{2})Step:7 ：(x = 3.0) and (x = -1.0)Step:8 ：(boxed{x = 3.0, x = -1.0})

Answer

Step: 1 ：Given the quadratic equation: (f(x) = x^2 - 2x - 3)Step: 2 ：Use the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a})Step: 3 ：Substitute the coefficients: a = 1, b = -2, c = -3Step: 4 ：Calculate the discriminant: (b^2 - 4ac = 16)Step: 5 ：Find the roots: (x = frac{-(-2) pm sqrt{16}}{2(1)})Step: 6 ：(x = frac{2 pm 4}{2})Step: 7 ：(x = 3.0) and (x = -1.0)Step: 8 ：(boxed{x = 3.0, x = -1.0})

a) $f(x)=x^{2}-2 x-3$

Answer

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