Problem

(C) $x=\frac{29 \sin 61^{\circ}}{\sin 79^{\circ}}$
(D) $x=\frac{21 \sin 40^{\circ}}{\sin 79^{\circ}}$
9 Let $f(x)=x^{3}-\left(k^{2}-4\right) x+1$
For which of the values of $k$ below is $f(x)$ many-to-one?
(A) $k=2$
(B) $k=-2$
(C) $k=1$
(D) $k=-4$

Answer

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Answer

Final Answer: \(\boxed{1}, \boxed{-4}\)

Steps

Step 1 :Find the derivative of the function: \(f'(x) = 3x^2 - (k^2 - 4)\)

Step 2 :Find the critical points: \(x = \pm\frac{\sqrt{3k^2 - 12}}{3}\)

Step 3 :Check for which values of k there are multiple critical points: \(k = 1, -4\)

Step 4 :Final Answer: \(\boxed{1}, \boxed{-4}\)

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