f) $2 x^{2}+3 x-20$
Final Answer: The roots of the quadratic equation are \(\boxed{2.5}\) and \(\boxed{-4.0}\)
Step 1 :Given the quadratic equation: \(2x^2 + 3x - 20 = 0\)
Step 2 :Using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 2\), \(b = 3\), and \(c = -20\)
Step 3 :Calculate the discriminant: \(169\)
Step 4 :Find the roots: \(x_1 = 2.5\) and \(x_2 = -4.0\)
Step 5 :Final Answer: The roots of the quadratic equation are \(\boxed{2.5}\) and \(\boxed{-4.0}\)