The point $(24,10)$ is on the terminal arm of an angle $\theta$ in standard position. Find $\sin \theta$ and $\cos \theta$.
The point $(-6,8)$ is on the terminal arm of an angle $\theta$ in standard

Step 1 ：Let the point (24, 10) be on the terminal arm of an angle \(\theta\) in standard position.

Step 2 ：Calculate the distance from the origin to the point (24, 10) using the Pythagorean theorem: \(\text{distance} = \sqrt{x^2 + y^2}\)

Step 3 ：\(\text{distance} = \sqrt{24^2 + 10^2} = 26\)

Step 4 ：Find the sine and cosine of the angle by dividing the y-coordinate and x-coordinate by the distance, respectively: \(\sin \theta = \frac{y}{\text{distance}}\) and \(\cos \theta = \frac{x}{\text{distance}}\)

Step 5 ：\(\sin \theta = \frac{10}{26} = \boxed{0.3846}\)

Step 6 ：\(\cos \theta = \frac{24}{26} = \boxed{0.9231}\)