Problem

$6 \mathrm{fl}$. oz. of a saline solution was mixed with $2 \mathrm{fl}$. oz. of pure water to make a $45 \%$ saline solution. Find the percent concentration of the first solution.

Answer

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Answer

\(\boxed{60\%}\)

Steps

Step 1 ：Let the percent concentration of the first solution be x. Set up the equation: \(6x + 2(0) = 8(0.45)\)

Step 2 ：Solve for x: \(x = \frac{8(0.45)}{6}\)

Step 3 ：Calculate x: \(x = 0.6\)

Step 4 ：\(\boxed{60\%}\)

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