Problem

8. Express $y=-3 x^{2}+12 x-2$ in the form $y=a(x-h)^{2}+k$, by completing the square and sketch the graph using a table of values. Label the vertex and axis of symmetry on the sketch.

Answer

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Answer

\(\boxed{y = -3(x-2)^2 + 10}\), vertex = (2, 10), axis of symmetry = x = 2, table of values = \([(0, -2), (1, 7), (2, 10), (3, 7), (4, -2)]\)

Steps

Step 1 :Rewrite the given quadratic equation in the form y = a(x-h)^2 + k by completing the square: \(y = -3x^2 + 12x - 2\)

Step 2 :Factor out the coefficient of the x^2 term: \(y = -3(x^2 - 4x) - 2\)

Step 3 :Complete the square inside the parentheses: \(y = -3(x^2 - 4x + 4) - 2 + 3(4)\)

Step 4 :Simplify the equation: \(y = -3(x - 2)^2 + 10\)

Step 5 :Identify the vertex and axis of symmetry: vertex = (2, 10), axis of symmetry = x = 2

Step 6 :Create a table of values for the graph: \([(0, -2), (1, 7), (2, 10), (3, 7), (4, -2)]\)

Step 7 :\(\boxed{y = -3(x-2)^2 + 10}\), vertex = (2, 10), axis of symmetry = x = 2, table of values = \([(0, -2), (1, 7), (2, 10), (3, 7), (4, -2)]\)

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