Problem

The function \( f(x)=\frac{1}{1-2 \sin x} \) is discontinuous at
\( f \) is continuous everywhere.
\( x=0 \)
\( x=\frac{\pi}{2} \)
\( x=\frac{\pi}{6} \)

Answer

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Answer

\( x = \frac{\pi}{6} \),\( \frac{5\pi}{6} \)

Steps

Step 1 ：\( 1-2 \sin x = 0 \)

Step 2 ：\( \sin x = \frac{1}{2} \)

Step 3 ：\( x = \frac{\pi}{6} \),\( \frac{5\pi}{6} \)

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