bif |x|=frac{4 x-3}{2}

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Accepted Answer

Step:1 ：Consider two cases: when x is positive or zero, and when x is negative.Step:2 ：Case 1: x >= 0, |x| = x, so the equation becomes: (x = frac{4x - 3}{2})Step:3 ：Case 2: x < 0, |x| = -x, so the equation becomes: (-x = frac{4x - 3}{2})Step:4 ：Solve the two equations separately:Step:5 ：(x = frac{4x - 3}{2}) gives x = (frac{3}{2})Step:6 ：(-x = frac{4x - 3}{2}) gives x = (frac{1}{2})Step:7 ：Combine the solutions: (boxed{x = frac{3}{2}, x = frac{1}{2}})

Answer

Step: 1 ：Consider two cases: when x is positive or zero, and when x is negative.Step: 2 ：Case 1: x >= 0, |x| = x, so the equation becomes: (x = frac{4x - 3}{2})Step: 3 ：Case 2: x < 0, |x| = -x, so the equation becomes: (-x = frac{4x - 3}{2})Step: 4 ：Solve the two equations separately:Step: 5 ：(x = frac{4x - 3}{2}) gives x = (frac{3}{2})Step: 6 ：(-x = frac{4x - 3}{2}) gives x = (frac{1}{2})Step: 7 ：Combine the solutions: (boxed{x = frac{3}{2}, x = frac{1}{2}})

bif $|x|=\frac{4 x-3}{2}$

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