Problem

What is the resultant magnitude of forces \( F 1+F 2+F 3 \), if \( F 1=40 \mathrm{kN}, \mathrm{F} 2=30 \mathrm{kN} \), and \( F 3=50 \mathrm{kN} \), and angle "a" \( =230 \) degrees, angle "b" \( =310 \) degrees, and the direction of \( F 3=0 \) degrees? Use force units and no decimal points

Answer

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Answer

\( R = \sqrt{R_x^2 + R_y^2} \)

Steps

Step 1 :\( F_1x = 40 \cos{230^\circ} \), \( F_1y = 40 \sin{230^\circ} \)

Step 2 :\( F_2x = 30 \cos{310^\circ} \), \( F_2y = 30 \sin{310^\circ} \)

Step 3 :\( R_x = F_1x + F_2x + F_3x \), \( R_y = F_1y + F_2y + F_3y \)

Step 4 :\( R = \sqrt{R_x^2 + R_y^2} \)

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