Revise for Enut of Vaar Mock
ind $\int \frac{5 x^{4}-7}{3 x^{3}} d x$ writing your answer in simplest form

Answer

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Answer

$\boxed{\frac{5x^2}{6} + \frac{7}{6x^2} + C}$ is the final answer

Steps

Step 1 ：Given the function: $\frac{5x^4 - 7}{3x^3}$

Step 2 ：Simplify the function by dividing each term by $3x^3$: $\frac{5x^4}{3x^3} - \frac{7}{3x^3}$

Step 3 ：Further simplify: $\frac{5}{3}x - \frac{7}{3x^3}$

Step 4 ：Find the integral of each term separately: $\int\frac{5}{3}x dx - \int\frac{7}{3x^3} dx$

Step 5 ：Integrate: $\frac{5}{6}x^2 + \frac{7}{6x^2} + C$

Step 6 ：$\boxed{\frac{5x^2}{6} + \frac{7}{6x^2} + C}$ is the final answer