(8) x^{2}+7 x+10=0

Question

(8) x^{2}+7 x+10=0

Accepted Answer

Step:1 ：Given the quadratic equation: (x^{2}+7 x+10=0)Step:2 ：Using the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a})Step:3 ：Substitute the coefficients: (a = 1), (b = 7), and (c = 10)Step:4 ：Calculate the discriminant: (Delta = b^2 - 4ac = 9)Step:5 ：Find the two solutions: (x_1 = frac{-7 - sqrt{9}}{2}) and (x_2 = frac{-7 + sqrt{9}}{2})Step:6 ：(boxed{x_1 = -2}), (boxed{x_2 = -5})

Answer

Step: 1 ：Given the quadratic equation: (x^{2}+7 x+10=0)Step: 2 ：Using the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a})Step: 3 ：Substitute the coefficients: (a = 1), (b = 7), and (c = 10)Step: 4 ：Calculate the discriminant: (Delta = b^2 - 4ac = 9)Step: 5 ：Find the two solutions: (x_1 = frac{-7 - sqrt{9}}{2}) and (x_2 = frac{-7 + sqrt{9}}{2})Step: 6 ：(boxed{x_1 = -2}), (boxed{x_2 = -5})

(8) $x^{2}+7 x+10=0$

Answer

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