a) x^{2}-14 x+24=0

Question

a) x^{2}-14 x+24=0

Accepted Answer

Step:1 ：Given the quadratic equation: (x^{2}-14 x+24=0)Step:2 ：Use the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a})Step:3 ：Identify the coefficients: (a = 1), (b = -14), and (c = 24)Step:4 ：Calculate the discriminant: (Delta = b^2 - 4ac = 100)Step:5 ：Find the solutions: (x1 = frac{-(-14) + sqrt{100}}{2(1)} = 12) and (x2 = frac{-(-14) - sqrt{100}}{2(1)} = 2)Step:6 ：(boxed{x1 = 12, x2 = 2})

Answer

Step: 1 ：Given the quadratic equation: (x^{2}-14 x+24=0)Step: 2 ：Use the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a})Step: 3 ：Identify the coefficients: (a = 1), (b = -14), and (c = 24)Step: 4 ：Calculate the discriminant: (Delta = b^2 - 4ac = 100)Step: 5 ：Find the solutions: (x1 = frac{-(-14) + sqrt{100}}{2(1)} = 12) and (x2 = frac{-(-14) - sqrt{100}}{2(1)} = 2)Step: 6 ：(boxed{x1 = 12, x2 = 2})

a) $x^{2}-14 x+24=0$

Answer

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