26. Determine the length of chord CD. [4 marks]
The final answer is \(\boxed{2\sqrt{5}}\).
Step 1 :Let the center of the circle be O, and let the point where the radius of the circle bisects the chord be E. Thus, the line segment from the center of the circle to point E has length 2, and we have \(\triangle ODE\) with a leg of 2 and a hypotenuse of 3.
Step 2 :Using the Pythagorean theorem, we can find the length of the other leg, DE: \(DE^2 = 3^2 - 2^2 = 5\), so \(DE = \sqrt{5}\).
Step 3 :Since DE is \(\frac{CD}{2}\), we can find the length of chord CD: \(CD = 2 \times DE = 2 \times \sqrt{5}\).
Step 4 :The final answer is \(\boxed{2\sqrt{5}}\).