Hence plot the graph of $y=3 x^{2}+2$.
Now, we can plot the graph of the given equation. The vertex is at $(0, 2)$, and the parabola opens upwards.
Step 1 :First, we need to understand the given equation $y = 3x^2 + 2$. It represents a parabola with a vertical axis of symmetry and vertex at $(0, 2)$.
Step 2 :The parabola opens upwards since the coefficient of the $x^2$ term is positive.
Step 3 :Now, we can plot the graph of the given equation. The vertex is at $(0, 2)$, and the parabola opens upwards.