Problem

The graph of $y=\tan x$ for $0^{\circ} \leq x \leq 360^{\circ}$ is shown below.
Solve $\tan x=\tan 38^{\circ}$ when $90^{\circ} \leq x \leq 360^{\circ}$.

Answer

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Answer

\(\boxed{x = 218^\circ}\)

Steps

Step 1 :Given the equation \(y = \tan x\) for \(0^\circ \leq x \leq 360^\circ\)

Step 2 :Solve \(\tan x = \tan 38^\circ\) when \(90^\circ \leq x \leq 360^\circ\)

Step 3 :Since the tangent function has a period of 180 degrees, we can add 180 degrees to 38 degrees to find another solution within the given range

Step 4 :\(x = 38^\circ + 180^\circ\)

Step 5 :\(x = 218^\circ\)

Step 6 :\(\boxed{x = 218^\circ}\)

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