The graph of $y=\sin x$ for $0^{\circ} \leq x \leq 360^{\circ}$ is shown below.
What are the coordinates of the minimum point of $y=\sin x$ for
\[
0^{\circ} \leq x \leq 360^{\circ} ?
\]

Answer

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Answer

$\boxed{\text{The coordinates of the minimum point of } y=\sin(x) \text{ for } 0^\circ \leq x \leq 360^\circ \text{ are } (270, -1)}$

Steps

Step 1 ：First, we need to find the minimum value of the sine function in the given range. We know that the sine function has a minimum value of -1. We need to find the value of x for which sin(x) = -1 in the given range.

Step 2 ：min_x = 270

Step 3 ：min_y = -1.0

Step 4 ：$\boxed{\text{The coordinates of the minimum point of } y=\sin(x) \text{ for } 0^\circ \leq x \leq 360^\circ \text{ are } (270, -1)}$

The graph of $y=\sin x$ for $0^{\circ} \leq x \leq 360^{\circ}$ is shown below.What are the coordinates of the minimum point of $y=\sin x$ for\[0^{\circ} \leq x \leq 360^{\circ} ?\]

Answer

Popular Problems

The graph of $y=\sin x$ for $0^{\circ} \leq x \leq 360^{\circ}$ is shown below.
What are the coordinates of the minimum point of $y=\sin x$ for
\[
0^{\circ} \leq x \leq 360^{\circ} ?
\]