Points: 0 of 1
Solve the following problem using a system of equations.
The two top concert tours in 2016 were concert A and concert B. Based on average ticket prices, it cost a total of $\$ 1261$ to purchase five tickets for concert A and six tickets for concert B. Three tickets for concert A and three tickets for concert B cost a total of $\$ 687$. How much did an average ticket cost for each tour?
The average ticket cost for concert $\mathrm{A}$ is $\$ \square$, and the average ticket cost for concert $\mathrm{B}$ is $\$ \square$. (Simplify your answers.)
Answer
Final Answer: The average ticket cost for concert A is \(\boxed{113}\) dollars, and the average ticket cost for concert B is \(\boxed{116}\) dollars.
Step 1 ：Let's denote the average ticket price for concert A as 'a' and for concert B as 'b'.
Step 2 ：From the problem, we can form the following two equations: \(5a + 6b = 1261\) and \(3a + 3b = 687\).
Step 3 ：We can solve this system of equations to find the values of 'a' and 'b', which represent the average ticket prices for concerts A and B respectively.
Step 4 ：Solving the equations, we get 'a' as 113 and 'b' as 116.
Step 5 ：Final Answer: The average ticket cost for concert A is \(\boxed{113}\) dollars, and the average ticket cost for concert B is \(\boxed{116}\) dollars.
