Problem

Find $\frac{d y}{d x}$ for the following function
\[
y=6 \sin x+9 \cos x
\]

Answer

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Answer

Final Answer: The derivative of the function \(y=6 \sin x+9 \cos x\) is \(\boxed{-9 \sin x+6 \cos x}\).

Steps

Step 1 :Given the function \(y=6 \sin x+9 \cos x\).

Step 2 :We need to find the derivative of the function.

Step 3 :The derivative of \(\sin x\) is \(\cos x\) and the derivative of \(\cos x\) is \(-\sin x\).

Step 4 :Applying these rules to the given function, we get \(\frac{d y}{d x} = -9\sin x + 6\cos x\).

Step 5 :Final Answer: The derivative of the function \(y=6 \sin x+9 \cos x\) is \(\boxed{-9 \sin x+6 \cos x}\).

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