Use basic identities to $\operatorname{simplify} \sin ^{3} x+\cos ^{2} x \sin x$.
Enclose arguments of functions in parentheses. For example, $\sin (2 x)$.
Remember that writing $\sin (x)$ to the fourth power as $\sin ^{4}(x)$ is just a mathematical shorthand. You should write it as $(\sin (x))^{4}$, which is what Mobius expects.
\[
\sin ^{3} x+\cos ^{2} x \sin x=
\]

Answer

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Answer

$\boxed{\sin(x)}$ is the final answer

Steps

Step 1 ：Rewrite the expression as $\sin^2(x) \sin(x) + \cos^2(x) \sin(x)$

Step 2 ：Factor out $\sin(x)$ to get $(\sin^2(x) + \cos^2(x))\sin(x)$

Step 3 ：Use the Pythagorean identity $\sin^2(x) + \cos^2(x) = 1$ to simplify

Step 4 ：$\boxed{\sin(x)}$ is the final answer