Problem

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1. Identify one of the products of each of the retctions of ethanol in acidic, baeis, and neurral solutions of $\mathrm{KHnO}_{4}$ given the fellowing informatien:
- a green cclour indicates the presence ef MnO).
- a lighi pink colour indicates Mnt,
- the brown precipilate is $\mathrm{MnO}_{2}$

Answer

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Answer

Summarize the findings: \(\boxed{\text{Acidic solution: Acetic acid (CH3COOH) and Mn2+ (light pink color)}}\), \(\boxed{\text{Basic solution: Acetic acid (CH3COOH) and MnO2 (brown precipitate)}}\), and \(\boxed{\text{Neutral solution: MnO4- (green color)}}\)

Steps

Step 1 :Identify the products of the reactions of ethanol in acidic, basic, and neutral solutions of KMnO4 using the given information about colors:

Step 2 :In an acidic solution, KMnO4 oxidizes ethanol to its highest possible oxidation state, which is a carboxylic acid (acetic acid, CH3COOH). The MnO4- ions will be reduced to Mn2+ ions, which have a light pink color.

Step 3 :In a basic solution, KMnO4 oxidizes ethanol to acetic acid (CH3COOH) and forms a brown precipitate, which indicates the presence of MnO2.

Step 4 :In a neutral solution, the green color indicates the presence of MnO4- ions, which means that the reaction is not very effective in oxidizing ethanol.

Step 5 :Summarize the findings: \(\boxed{\text{Acidic solution: Acetic acid (CH3COOH) and Mn2+ (light pink color)}}\), \(\boxed{\text{Basic solution: Acetic acid (CH3COOH) and MnO2 (brown precipitate)}}\), and \(\boxed{\text{Neutral solution: MnO4- (green color)}}\)

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