$f_{A C 1}=50 \mathrm{~Hz}$ ve $f_{A C 2}=60 \mathrm{~Hz}$
Verilen 4 frekans değerlerini şekilde verilenlere göre büyükten küçüğe sıralayınız.
Lütfen birini seçin:
a. $f_{A C 2}> f_{A C 1}> f_{D C 2}> f_{D C 1}$
b. $f_{A C 2}=f_{D C 2}> f_{A C 1}> f_{D C 1}$
c. $f_{A C 2}=f_{D C 2}> f_{A C 1}=f_{D C 1}$
d. $f_{D C 1}> f_{A C 1}> f_{D C 2}=f_{A C 2}$

Step 1 ：Given the frequencies $f_{AC1} = 50 Hz$ and $f_{AC2} = 60 Hz$, we need to find the frequencies $f_{DC1}$ and $f_{DC2}$ and then order all four frequencies from largest to smallest.

Step 2 ：We know that the frequency of a transformer is related to the number of turns in the primary and secondary coils. The relationship is given by: $$\frac{f_{primary}}{f_{secondary}} = \frac{N_{primary}}{N_{secondary}}$$

Step 3 ：For $f_{DC1}$, we have: $$\frac{f_{AC1}}{f_{DC1}} = \frac{N_{AC1}}{N_{DC1}}$$

Step 4 ：For $f_{DC2}$, we have: $$\frac{f_{AC2}}{f_{DC2}} = \frac{N_{AC2}}{N_{DC2}}$$

Step 5 ：Given the number of turns: $N_{AC1} = 100$, $N_{DC1} = 200$, $N_{AC2} = 100$, and $N_{DC2} = 150$, we can solve these equations for $f_{DC1}$ and $f_{DC2}$.

Step 6 ：Calculating $f_{DC1}$: $$f_{DC1} = \frac{f_{AC1} \times N_{DC1}}{N_{AC1}} = \frac{50 \times 200}{100} = 100 Hz$$

Step 7 ：Calculating $f_{DC2}$: $$f_{DC2} = \frac{f_{AC2} \times N_{DC2}}{N_{AC2}} = \frac{60 \times 150}{100} = 90 Hz$$

Step 8 ：Final Answer: The correct order of frequencies is $f_{AC2} > f_{DC2} > f_{AC1} > f_{DC1}$, which corresponds to option a. \(\boxed{f_{AC2}>f_{AC1}>f_{DC2}>f_{DC1}}\)