What is the factorization of the trinomial below?
\[
x^{2}-7 x+6
\]
A. $(x+3)(x-2)$
B. $(x-6)(x-1)$
C. $(x-3)(x-2)$
D. $(x+6)(x-1)$
Answer
\(\boxed{\text{Final Answer: The factorization of the trinomial } x^{2}-7 x+6 \text{ is } (x-6)(x-1)}\)
Step 1 ：The factorization of a quadratic trinomial of the form \(ax^2 + bx + c\) can be found by finding two numbers that add up to \(b\) and multiply to \(c\).
Step 2 ：In this case, we need to find two numbers that add up to -7 and multiply to 6.
Step 3 ：The numbers -1 and -6 fit these criteria, so the factorization of the trinomial is \((x - 1)(x - 6)\).
Step 4 ：\(x = x\)
Step 5 ：\(expr = x^2 - 7*x + 6\)
Step 6 ：\(factored_expr = (x - 6)*(x - 1)\)
Step 7 ：\(\boxed{\text{Final Answer: The factorization of the trinomial } x^{2}-7 x+6 \text{ is } (x-6)(x-1)}\)
