On a standardized exam, the scores are normally distributed with a mean of 55 and a standard deviation of 10. Find the z-score of a person who scored 36 on the exam.

Step 1 ：The problem provides that the scores on a standardized exam are normally distributed with a mean of 55 and a standard deviation of 10. We are asked to find the z-score of a person who scored 36 on the exam.

Step 2 ：The z-score is a measure of how many standard deviations an element is from the mean. To find the z-score, we subtract the mean score from the person's score and then divide by the standard deviation.

Step 3 ：The formula for calculating the z-score is: \(z = \frac{X - \mu}{\sigma}\), where \(X\) is the person's score, \(\mu\) is the mean score, and \(\sigma\) is the standard deviation.

Step 4 ：In this case, \(X = 36\), \(\mu = 55\), and \(\sigma = 10\). Substituting these values into the formula, we get: \(z = \frac{36 - 55}{10} = -1.9\).

Step 5 ：Final Answer: The z-score of a person who scored 36 on the exam is \(\boxed{-1.9}\).