1. Collapse the following polynomial using the Binomial Theorem. ( 2 marks)
\[
16 x^{4}+96 x^{3}+21 x^{2}+216 x+81
\]

Answer

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Answer

\(\boxed{\text{The polynomial cannot be collapsed using the Binomial Theorem.}}\)

Steps

Step 1 ：First, let's try to identify if this polynomial can be represented as a binomial expansion. We can start by looking for a common factor in all the terms.

Step 2 ：coefficients = [16, 96, 21, 216, 81]

Step 3 ：common_factor = 1

Step 4 ：Since the common factor is 1, there is no common factor that can be factored out from all the terms. Therefore, this polynomial cannot be represented as a binomial expansion using the Binomial Theorem.

Step 5 ：\(\boxed{\text{The polynomial cannot be collapsed using the Binomial Theorem.}}\)

1. Collapse the following polynomial using the Binomial Theorem. ( 2 marks)\[16 x^{4}+96 x^{3}+21 x^{2}+216 x+81\]

Answer

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1. Collapse the following polynomial using the Binomial Theorem. ( 2 marks)
\[
16 x^{4}+96 x^{3}+21 x^{2}+216 x+81
\]