x^{2}-10 x+25=0

Question

x^{2}-10 x+25=0

Accepted Answer

Step:1 ：Given the quadratic equation: (x^2 - 10x + 25 = 0)Step:2 ：Identify the coefficients: (a = 1), (b = -10), and (c = 25)Step:3 ：Calculate the discriminant: (Delta = b^2 - 4ac = (-10)^2 - 4(1)(25) = 100 - 100 = 0)Step:4 ：Since the discriminant is 0, there is only one real solution for the equation.Step:5 ：Use the quadratic formula: (x = frac{-b pm sqrt{Delta}}{2a} = frac{10 pm sqrt{0}}{2(1)})Step:6 ：Calculate the solution: (x = frac{10}{2} = 5)Step:7 ：(boxed{x = 5})

Answer

Step: 1 ：Given the quadratic equation: (x^2 - 10x + 25 = 0)Step: 2 ：Identify the coefficients: (a = 1), (b = -10), and (c = 25)Step: 3 ：Calculate the discriminant: (Delta = b^2 - 4ac = (-10)^2 - 4(1)(25) = 100 - 100 = 0)Step: 4 ：Since the discriminant is 0, there is only one real solution for the equation.Step: 5 ：Use the quadratic formula: (x = frac{-b pm sqrt{Delta}}{2a} = frac{10 pm sqrt{0}}{2(1)})Step: 6 ：Calculate the solution: (x = frac{10}{2} = 5)Step: 7 ：(boxed{x = 5})

$x^{2}-10 x+25=0$

Answer

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