The number of calories in 12 randomly selected microwave dinners is shown here.
\[
\begin{array}{llllllllllll}
1650 & 360 & 560 & 870 & 190 & 440 & 980 & 1030 & 650 & 900 & 410 & 730
\end{array}
\]
Find the standard deviation. Round the standard deviation to two decimal places, if necessary.

Step 1 ：First, calculate the mean (average) of the data set. The data set is \([1650, 360, 560, 870, 190, 440, 980, 1030, 650, 900, 410, 730]\). The mean is calculated as \(\frac{1650 + 360 + 560 + 870 + 190 + 440 + 980 + 1030 + 650 + 900 + 410 + 730}{12} = 730.83\)

Step 2 ：Next, subtract the mean from each data point and square the result. This gives us \([844867.36, 137517.36, 29184.03, 19367.36, 292500.69, 84584.03, 62084.03, 89500.69, 6534.03, 28617.36, 102934.03, 0.69]\)

Step 3 ：Then, calculate the mean of these squared differences. This is done by adding all the squared differences and dividing by the number of data points. The mean of the squared differences is \(\frac{844867.36 + 137517.36 + 29184.03 + 19367.36 + 292500.69 + 84584.03 + 62084.03 + 89500.69 + 6534.03 + 28617.36 + 102934.03 + 0.69}{12} = 141474.31\)

Step 4 ：Finally, take the square root of the result to get the standard deviation. The standard deviation is \(\sqrt{141474.31} = 376.13\)

Step 5 ：Final Answer: The standard deviation of the given data set is \(\boxed{376.13}\)