begin{array}{l}X quad Y=2^{x} quad(x, y) X=F cdot(x)-3,-2,-1,0,1,2,3end{array}

Question

begin{array}{l}X quad Y=2^{x} quad(x, y)  X=F cdot(x)-3,-2,-1,0,1,2,3end{array}

Accepted Answer

Step:1 ：Find the values of X using the given function X = F(x) - 3, where x = -3, -2, -1, 0, 1, 2, 3: (X_{values} = [-6, -5, -4, -3, -2, -1, 0])Step:2 ：Find the corresponding values of Y using the function Y = 2^X: (Y_{values} = [0.015625, 0.03125, 0.0625, 0.125, 0.25, 0.5, 1])Step:3 ：Combine the X and Y values to get the final answer: (boxed{(-6, 0.015625), (-5, 0.03125), (-4, 0.0625), (-3, 0.125), (-2, 0.25), (-1, 0.5), (0, 1)})

Answer

Step: 1 ：Find the values of X using the given function X = F(x) - 3, where x = -3, -2, -1, 0, 1, 2, 3: (X_{values} = [-6, -5, -4, -3, -2, -1, 0])Step: 2 ：Find the corresponding values of Y using the function Y = 2^X: (Y_{values} = [0.015625, 0.03125, 0.0625, 0.125, 0.25, 0.5, 1])Step: 3 ：Combine the X and Y values to get the final answer: (boxed{(-6, 0.015625), (-5, 0.03125), (-4, 0.0625), (-3, 0.125), (-2, 0.25), (-1, 0.5), (0, 1)})

$\begin{array}{l}X \quad Y=2^{x} \quad(x, y) \\ X=F \cdot(x)-3,-2,-1,0,1,2,3\end{array}$

Answer

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