What value of $c$ will complete the square in the expression below and make the expression a perfect square trinomial?
\[
x^{2}+16 x+c
\]
$c=$
Enter the perfect square trinomial as a squared binomial.
Final Answer: $c = \boxed{64}$
Step 1 :To complete the square, we need to find a value of $c$ such that the expression $x^{2}+16 x+c$ becomes a perfect square trinomial. A perfect square trinomial is of the form $(x+a)^2 = x^2 + 2ax + a^2$.
Step 2 :Comparing this with the given expression, we can see that $2a$ is equivalent to $16$. Solving for $a$ gives $a = 8$.
Step 3 :Therefore, $c$ should be $a^2 = 8^2 = 64$.
Step 4 :Final Answer: $c = \boxed{64}$