If ( X^{3}-Y^{3}=26, X-Y=2 ) then ( X^{2}+X Y+Y^{2}=cdots )

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Accepted Answer

Step:1 ：1. X=Y+2Step:2 ：2. Substitute X in (X^3-Y^3=26): ((Y+2)^3-Y^3=26)Step:3 ：3. Solve for Y: Y=3Step:4 ：4. Solve for X: X=5Step:5 ：5. Substitute X, Y in (X^2+XY+Y^2): (5^2+5(3)+3^2)

Answer

Step: 1 ：1. X=Y+2Step: 2 ：2. Substitute X in (X^3-Y^3=26): ((Y+2)^3-Y^3=26)Step: 3 ：3. Solve for Y: Y=3Step: 4 ：4. Solve for X: X=5Step: 5 ：5. Substitute X, Y in (X^2+XY+Y^2): (5^2+5(3)+3^2)

If $X^{3} - Y^{3} = 26, X - Y = 2$ then $X^{2} + X Y + Y^{2} = \dots$

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Popular Problems

If X3−Y3=26,X−Y=2 then X2+XY+Y2=⋯

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Popular Problems

If $X^{3} - Y^{3} = 26, X - Y = 2$ then $X^{2} + X Y + Y^{2} = \dots$