The solution set of The equation \( X^{2}+4=0 \) in \( \mathrm{R} \) is.......
Therefore, the solution set is \( \emptyset \)
Step 1 :Rewrite as \(X^{2}=-4\)
Step 2 :Since no real number squared equals a negative number, there are no solutions in \( \mathrm{R} \)
Step 3 :Therefore, the solution set is \( \emptyset \)