Problem

If \( (a+b)^{2}=25, a b=6 \) then \( a^{2}+b^{2}=\cdots \)

Answer

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Answer

Step 3: Solve for \(a^{2}+b^{2}\): \(a^{2}+b^{2}=25-12=13\)

Steps

Step 1 :Step 1: Expand \((a+b)^{2}\) using the formula \((a+b)^{2}=a^{2}+2ab+b^{2}\)

Step 2 :Step 2: Substitute given values: \(25=a^{2}+2(6)+b^{2}\)

Step 3 :Step 3: Solve for \(a^{2}+b^{2}\): \(a^{2}+b^{2}=25-12=13\)

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