frac{x}{x^{2}+3 x+2}-frac{3 x-2}{x^{2}+8 x+7}

Question

Accepted Answer

Step:1 ：Factor the denominators: frac{x}{(x+1)(x+2)} - frac{3x-2}{(x+1)(x+7)}Step:2 ：Find a common denominator: (x+1)(x+2)(x+7)Step:3 ：Combine the fractions: frac{-2x^2 + 3x + 4}{(x+1)(x+2)(x+7)}Step:4 ：Expand the denominator: frac{-2x^2 + 3x + 4}{x^3 + 10x^2 + 23x + 14}Step:5 ：(boxed{frac{-2x^2 + 3x + 4}{x^3 + 10x^2 + 23x + 14}})

Answer

Step: 1 ：Factor the denominators: frac{x}{(x+1)(x+2)} - frac{3x-2}{(x+1)(x+7)}Step: 2 ：Find a common denominator: (x+1)(x+2)(x+7)Step: 3 ：Combine the fractions: frac{-2x^2 + 3x + 4}{(x+1)(x+2)(x+7)}Step: 4 ：Expand the denominator: frac{-2x^2 + 3x + 4}{x^3 + 10x^2 + 23x + 14}Step: 5 ：(boxed{frac{-2x^2 + 3x + 4}{x^3 + 10x^2 + 23x + 14}})

$\frac{x}{x^{2}+3 x+2}-\frac{3 x-2}{x^{2}+8 x+7}$

Answer

Popular Problems