Problem

Find an approximation for the following if $\theta$ is small:
a) $\sin \theta \cos \theta$
b) $\theta \tan 5 \theta \sin \theta$
c) $\frac{\sin 4 \theta \cos 3 \theta}{2 \theta}$
d) $3 \tan \theta+\cos 2 \theta$
e) $\sin \frac{1}{2} \theta-\cos \theta$
f) $\frac{\cos \theta-\cos 2 \theta}{1-(\cos 3 \theta+3 \sin \theta \tan \theta)}$

Answer

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Answer

Final Answer: \(\boxed{a) \theta}\), \(\boxed{b) 5\theta^3}\), \(\boxed{c) 2}\), \(\boxed{d) 3\theta + 1}\), \(\boxed{e) \frac{1}{2}\theta - 1}\), \(\boxed{f) 0}\)

Steps

Step 1 :Use the following approximations for small angles: \(\sin \theta \approx \theta\), \(\cos \theta \approx 1\), and \(\tan \theta \approx \theta\)

Step 2 :Approximate the expressions using the above approximations:

Step 3 :a) \(\sin \theta \cos \theta \approx \theta \cdot 1 = \theta\)

Step 4 :b) \(\theta \tan 5 \theta \sin \theta \approx \theta \cdot 5\theta \cdot \theta = 5\theta^3\)

Step 5 :c) \(\frac{\sin 4 \theta \cos 3 \theta}{2 \theta} \approx \frac{4\theta \cdot 1}{2\theta} = 2\)

Step 6 :d) \(3 \tan \theta+\cos 2 \theta \approx 3\theta + 1\)

Step 7 :e) \(\sin \frac{1}{2} \theta-\cos \theta \approx \frac{1}{2}\theta - 1\)

Step 8 :f) \(\frac{\cos \theta-\cos 2 \theta}{1-(\cos 3 \theta+3 \sin \theta \tan \theta)} \approx \frac{1 - 1}{1 - (1 + 3\theta^2)} = \frac{0}{1 - 1 - 3\theta^2} = 0\)

Step 9 :Final Answer: \(\boxed{a) \theta}\), \(\boxed{b) 5\theta^3}\), \(\boxed{c) 2}\), \(\boxed{d) 3\theta + 1}\), \(\boxed{e) \frac{1}{2}\theta - 1}\), \(\boxed{f) 0}\)

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