The air temperature of a mountain drops by $4^{\circ} \mathrm{C}$ for every $1000 \mathrm{~m}$ of elevation.
If the air temperature is $25^{\circ} \mathrm{C}$ at the base of the mountain, at what elevation will the air temperature be $17^{\circ} \mathrm{C}$ ?

Answer

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Answer

$\boxed{2000}$ meters is the elevation at which the air temperature will be $17^\circ \mathrm{C}$

Steps

Step 1 ：Let x be the elevation difference. Then, we have the equation: $25 - \frac{x}{250} = 17$

Step 2 ：Solve for x: $x = 2000$

Step 3 ：$\boxed{2000}$ meters is the elevation at which the air temperature will be $17^\circ \mathrm{C}$