Each side length of Cube $A$ is $4 \mathrm{~cm}$ long.
Each side length of Cube $B$ is triple the side length of Cube $A$.
How many times greater is the volume of Cube $B$ than that of Cube A?
1664 times 192 times
27 times 9 times

Answer

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Answer

$\boxed{27}$ times greater.

Steps

Step 1 ：Let the side length of Cube A be $a$ and the side length of Cube B be $b$. Given that $b = 3a$, and $a = 4$ cm.

Step 2 ：Calculate the volume of Cube A: $V_A = a^3 = 4^3 = 64$ cubic cm.

Step 3 ：Calculate the side length of Cube B: $b = 3a = 3(4) = 12$ cm.

Step 4 ：Calculate the volume of Cube B: $V_B = b^3 = 12^3 = 1728$ cubic cm.

Step 5 ：Find how many times greater the volume of Cube B is than that of Cube A: $\frac{V_B}{V_A} = \frac{1728}{64} = 27$.

Step 6 ：$\boxed{27}$ times greater.