Find the coordinates of the \( y \)-intercept and the \( x \)-intercept, in that order.
\[
\begin{array}{l}
2 x+y=-6 \\
(-6,0)(6,0)
\end{array}
\]

Answer

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Answer

\(y\)-intercept: \(2x+y=-6\), \(x=0\) => \(2(0) + y = -6\) => \(y = -6\), so \((0,-6)\)

Steps

Step 1 ：\(x\)-intercept: \(2x+y=-6\), \(y=0\) => \(2x + 0 = -6\) => \(x = -3\), so \((-3,0)\)

Step 2 ：\(y\)-intercept: \(2x+y=-6\), \(x=0\) => \(2(0) + y = -6\) => \(y = -6\), so \((0,-6)\)