Problem

20.甲、乙两人沿400米环形跑道练习跑步，两人同时从跑道的同一地点向相反方向跑去。相遇后甲比原来 速度增加2米 / 秒，乙比原来速度减少2米 / 秒, 结果都用24秒同时回到原地。求甲原来的速度。

Answer

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Answer

3. Final Answer: \( \boxed{v1 = \frac{44}{3} \text{ m/s}} \)

Steps

Step 1 ：1. Set up the equations: \( (v1 + 2) * 24 = 400 \), \( (v2 - 2) * 24 = 400 \), and \( v1 * t1 = v2 * t2 \)

Step 2 ：2. Solve the equations to find the value of v1: \( v1 = \frac{44}{3} \) m/s

Step 3 ：3. Final Answer: \( \boxed{v1 = \frac{44}{3} \text{ m/s}} \)

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