Problem

A hole can be dug in one hour with a small shovel and in half an hour with a large shovel.
1. What is the RTS of labor time for shovel size?
2. What does the "one hole" isoquant look like? How much time would it take a worker to dig a hole if he or she used a small shovel for half the hole, then switched to the large shovel?

Answer

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Answer

\(\boxed{\text{2. If a worker used a small shovel for half the hole and then switched to the large shovel, it would take approximately 0.67 hours (or 40 minutes) to dig the hole}}\)

Steps

Step 1 :Let small_shovel_time = 1 hour and large_shovel_time = 0.5 hour

Step 2 :Calculate the rate of work done by each shovel: small_shovel_rate = \(\frac{1}{1}\) = 1.0 and large_shovel_rate = \(\frac{1}{0.5}\) = 2.0

Step 3 :\(\boxed{\text{1. The RTS of labor time for shovel size is 2.0}}\)

Step 4 :Calculate the combined_rate: \(\frac{1}{2}\) small_shovel_rate + \(\frac{1}{2}\) large_shovel_rate = \(\frac{1}{2}\)(1.0) + \(\frac{1}{2}\)(2.0) = 1.5

Step 5 :Calculate the time_taken to dig a hole using both shovels: \(\frac{1}{1.5}\) = \(\frac{2}{3}\) hours or 40 minutes

Step 6 :\(\boxed{\text{2. If a worker used a small shovel for half the hole and then switched to the large shovel, it would take approximately 0.67 hours (or 40 minutes) to dig the hole}}\)

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