Problem

22. The perimeter of a rectangle is 40 in. Twice the length of the rectangle is 20 minus twice the width. What are the length and width?

Answer

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Answer

\( L + W = 20 \)

Steps

Step 1 :\( P = 40 \)

Step 2 :\( 2L = 20 - 2W \)

Step 3 :\( L + W = 20 \)

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