Problem

5. Determine the $x$-intercepts and the vertex of the parabola. Show your work. Then graph the parabola.
\[
y=x^{2}-8 x+15
\]

Answer

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Answer

\(\boxed{\text{The x-intercepts are 3 and 5, and the vertex of the parabola is (4, -1)}}\)

Steps

Step 1 :Set y to 0 and solve for x: \(0 = x^2 - 8x + 15\)

Step 2 :Factor the equation: \((x - 3)(x - 5) = 0\)

Step 3 :Find the x-intercepts: \(x = 3\) and \(x = 5\)

Step 4 :Use the vertex formula \(x = \frac{-b}{2a}\) with a = 1 and b = -8: \(x = \frac{-(-8)}{2(1)} = 4\)

Step 5 :Plug the x-coordinate of the vertex back into the equation to find the y-coordinate: \(y = (4)^2 - 8(4) + 15 = -1\)

Step 6 :\(\boxed{\text{The x-intercepts are 3 and 5, and the vertex of the parabola is (4, -1)}}\)

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