Solve the following quadratic equation by factoring. If needed, write your answer as a fraction reduced to lowest terms.
\[
8 y^{2}+3 y+2=7 y^{2}+10 y-8
\]
Answer 2 Points
Answer
Final Answer: The solutions to the equation are \(y = 2\) and \(y = 5\). In Latex format, the final answer is \(\boxed{y = 2, y = 5}\).
Step 1 ：Rearrange the equation to the standard form of a quadratic equation, which is \(ax^2 + bx + c = 0\). In this case, we need to subtract \(7y^2\), \(10y\), and \(-8\) from both sides of the equation to get it in the standard form.
Step 2 ：Solve the equation \(y^2 - 7*y + 10 = 0\) to find the roots of the quadratic equation.
Step 3 ：The roots of the equation are \(y = 2\) and \(y = 5\).
Step 4 ：Final Answer: The solutions to the equation are \(y = 2\) and \(y = 5\). In Latex format, the final answer is \(\boxed{y = 2, y = 5}\).
