Based on the figure, select all true equations.
$\begin{array}{l} \cos (42^{\circ}) = \frac{b}{c} \\ \cos (48^{\circ}) = \frac{b}{c} \\ \sin (42^{\circ}) = \frac{b}{c} \\ \sin (48^{\circ}) = \frac{b}{c} \\ \tan (42^{\circ}) = \frac{b}{a} \\ \tan (48^{\circ}) = \frac{b}{b} \end{array}$

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Using the trigonometric functions, we find the true equations to be: $\cos (42^{\circ}) = \frac{b}{c}$ , $\sin (48^{\circ}) = \frac{b}{c}$ , and $\tan (42^{\circ}) = \frac{b}{a}$ .

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Step 1 ：Given a right triangle with angle measures 42°, 48°, and 90°, we can use trigonometric functions to find the true equations.

Step 2 ：Using the trigonometric functions, we find the true equations to be: $\cos (42^{\circ}) = \frac{b}{c}$ , $\sin (48^{\circ}) = \frac{b}{c}$ , and $\tan (42^{\circ}) = \frac{b}{a}$ .

Based on the figure, select all true equations.cos⁡(42∘)=bccos⁡(48∘)=bcsin⁡(42∘)=bcsin⁡(48∘)=bctan⁡(42∘)=batan⁡(48∘)=bb

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Based on the figure, select all true equations.
$\begin{array}{l} \cos (42^{\circ}) = \frac{b}{c} \\ \cos (48^{\circ}) = \frac{b}{c} \\ \sin (42^{\circ}) = \frac{b}{c} \\ \sin (48^{\circ}) = \frac{b}{c} \\ \tan (42^{\circ}) = \frac{b}{a} \\ \tan (48^{\circ}) = \frac{b}{b} \end{array}$