Given that $g(x)=\frac{x-5}{x+8}$, find each of the following.
a) $g(9)$
b) $g(5)$
c) $g(-8)$
d) $g(-19.25)$
e) $g(x+h)$

Step 1 ：First, we substitute the given values into the function $g(x)=\frac{x-5}{x+8}$.

Step 2 ：a) For $g(9)$, we substitute $x=9$ into the function: $g(9)=\frac{9-5}{9+8}=\frac{4}{17}$.

Step 3 ：b) For $g(5)$, we substitute $x=5$ into the function: $g(5)=\frac{5-5}{5+8}=\frac{0}{13}=0$.

Step 4 ：c) For $g(-8)$, we substitute $x=-8$ into the function: $g(-8)=\frac{-8-5}{-8+8}=\frac{-13}{0}$, which is undefined because we cannot divide by zero.

Step 5 ：d) For $g(-19.25)$, we substitute $x=-19.25$ into the function: $g(-19.25)=\frac{-19.25-5}{-19.25+8}=\frac{-24.25}{-11.25}=2.15$.

Step 6 ：e) For $g(x+h)$, we substitute $x+h$ into the function: $g(x+h)=\frac{(x+h)-5}{(x+h)+8}=\frac{x+h-5}{x+h+8}$.

Step 7 ：So, the solutions are: $g(9)=\boxed{\frac{4}{17}}$, $g(5)=\boxed{0}$, $g(-8)$ is undefined, $g(-19.25)=\boxed{2.15}$, and $g(x+h)=\boxed{\frac{x+h-5}{x+h+8}}$.