Consider the indefinite integral $\int e^{3 x+5} d x$ :
a) This can be transformed into a basic integral by letting
\[
u=
\]
and
\[
d u=
\]
Final Answer: \(\boxed{\frac{1}{3}e^{3x+5} + C}\)
Step 1 :Let's consider the indefinite integral \(\int e^{3 x+5} d x\)
Step 2 :We can simplify this integral by using the substitution method. Let's let \(u = 3x + 5\)
Step 3 :The differential \(du\) would be the derivative of \(u\) with respect to \(x\), which is \(3 dx\)
Step 4 :In our integral, we have \(dx\), not \(3dx\). To correct for this, we can divide both sides of the equation \(du = 3 dx\) by \(3\) to get \(du/3 = dx\)
Step 5 :We can then substitute \(u\) and \(du/3\) into the integral
Step 6 :The integral of \(e^{3x+5}\) with respect to \(x\) is \(\frac{1}{3}e^{3x+5} + C\), where \(C\) is the constant of integration
Step 7 :Final Answer: \(\boxed{\frac{1}{3}e^{3x+5} + C}\)