frac{1-tan ^{2} 22 frac{1^{circ}}{2}}{1+tan ^{2} 22 frac{1^{circ}}{2}} is equal to :-

Question

Accepted Answer

Step:1 ：Use the identity (tan^2 x = frac{1 - cos 2x}{1 + cos 2x}) to simplify the expressionStep:2 ：Calculate (cos 2x) for (x = 22.5^circ)Step:3 ：Substitute the value of (cos 2x) into the expressionStep:4 ：Simplify the expression to get the final answerStep:5 ：(boxed{0.7071})

Answer

Step: 1 ：Use the identity (tan^2 x = frac{1 - cos 2x}{1 + cos 2x}) to simplify the expressionStep: 2 ：Calculate (cos 2x) for (x = 22.5^circ)Step: 3 ：Substitute the value of (cos 2x) into the expressionStep: 4 ：Simplify the expression to get the final answerStep: 5 ：(boxed{0.7071})

$\frac{1-\tan ^{2} 22 \frac{1^{\circ}}{2}}{1+\tan ^{2} 22 \frac{1^{\circ}}{2}}$ is equal to :-

Answer

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